A person cannot see objects clearly beyond 2. | vedclass

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(D) The person is suffering from myopia (nearsightedness) because they cannot see objects beyond a certain distance $(2.0 \, m)$.To correct this defec

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$- 0.5 \, D$

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(D) The person is suffering from myopia (nearsightedness) because they cannot see objects beyond a certain distance $(2.0 \, m)$.To correct this defect, a concave lens is used.The far point of the person is $v = - 2.0 \, m$.We want the person to be able to see objects at infinity, so the object distance is $u = \infty$.Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.$\frac{1}{f} = \frac{1}{- 2.0} - \frac{1}{\infty} = - 0.5 \, m^{-1}$.Power $P = \frac{1}{f (in \, meters)} = - 0.5 \, D$.

$(I)$ Presbyopia	$(A)$ Sphero-cylindrical lens
$(II)$ Hypermetropia	$(B)$ Convex lens of proper power may be used close to the eye
$(III)$ Astigmatism	$(C)$ Concave lens of suitable focal length
$(IV)$ Myopia	$(D)$ Bifocal lens of suitable focal length

$A$ person cannot see objects clearly beyond $2.0 \, m$. The power of the lens required to correct his vision will be:

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