A person covers a distance of 100, km in 10, | vedclass

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(A) Using the method of alligation:Let the speed of walking be $7\, km/h$ and the speed of running be $12\, km/h$.The average speed is $\frac{100\, km

Vedclass · Accepted Answer

$28, 72$

Vedclass · Answer

(A) Using the method of alligation:Let the speed of walking be $7\, km/h$ and the speed of running be $12\, km/h$.The average speed is $\frac{100\, km}{10\, h} = 10\, km/h$.Applying alligation:$|12 - 10| = 2$$|7 - 10| = 3$The ratio of time taken for walking to running is $2:3$.Total time = $10\, hours$.Time taken for walking = $\frac{2}{2+3} 	imes 10 = 4\, hours$.Time taken for running = $\frac{3}{2+3} 	imes 10 = 6\, hours$.Distance covered by walking = $7\, km/h 	imes 4\, h = 28\, km$.Distance covered by running = $12\, km/h 	imes 6\, h = 72\, km$.Thus,the distances are $28\, km$ and $72\, km$.

$A$ person covers a distance of $100\, km$ in $10\, hours$,partly by walking at $7\, km/h$ and the rest by running at $12\, km/h$. Find out the distance covered in each part (in $km$).

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