300 gm of sugar solution contains 40 % sugar. | vedclass

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(C) Initial amount of solution $= 300 \ gm$.Amount of sugar $= 40 \%$ of $300 = \frac{40}{100} 	imes 300 = 120 \ gm$.Amount of water $= 300 - 120 = 1

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(C) Initial amount of solution $= 300 \ gm$.Amount of sugar $= 40 \%$ of $300 = \frac{40}{100} 	imes 300 = 120 \ gm$.Amount of water $= 300 - 120 = 180 \ gm$.Let the amount of sugar to be added be $x \ gm$.After adding sugar,the new amount of sugar $= 120 + x$.The total amount of solution becomes $= 300 + x$.We want the new concentration of sugar to be $50 \%$,so:$\frac{120 + x}{300 + x} = \frac{50}{100} = \frac{1}{2}$.Cross-multiplying gives: $2(120 + x) = 300 + x$.$240 + 2x = 300 + x$.$2x - x = 300 - 240$.$x = 60 \ gm$.

$300$ $gm$ of sugar solution contains $40 \%$ sugar. How much sugar (in $gm$) should be added to make the concentration $50 \%$ in the solution?

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