A person was to multiply a fraction by frac{6 | vedclass

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Question

(B) Let the fraction be $x$.According to the problem,the person divided by $\frac{6}{7}$ instead of multiplying by $\frac{6}{7}$.This means the calcul

Vedclass · Accepted Answer

$\frac{36}{91}$

Vedclass · Answer

(B) Let the fraction be $x$.According to the problem,the person divided by $\frac{6}{7}$ instead of multiplying by $\frac{6}{7}$.This means the calculated value is $x \div \frac{6}{7} = \frac{7}{6}x$.The correct answer should have been $\frac{6}{7}x$.Given that the calculated value exceeds the correct answer by $\frac{1}{7}$,we have:$\frac{7}{6}x - \frac{6}{7}x = \frac{1}{7}$To solve for $x$,find a common denominator for the fractions on the left side,which is $42$:$\frac{49x - 36x}{42} = \frac{1}{7}$$\frac{13x}{42} = \frac{1}{7}$$x = \frac{1}{7} 	imes \frac{42}{13} = \frac{6}{13}$Now,calculate the correct answer:Correct answer $= \frac{6}{7}x = \frac{6}{7} 	imes \frac{6}{13} = \frac{36}{91}$.

$A$ person was to multiply a fraction by $\frac{6}{7}$. Instead,he divided the fraction by $\frac{6}{7}$ and got an answer which exceeds the correct answer by $\frac{1}{7}$. The correct answer is:

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