A piece of marble is projected from the Earth | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The initial velocity is $u = 19.6 \sqrt{2} \ m/s$ at an angle $	heta = 45^{\circ}$.Horizontal component: $u_x = u \cos(45^{\circ}) = 19.6 \sqrt{2

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(D) The initial velocity is $u = 19.6 \sqrt{2} \ m/s$ at an angle $	heta = 45^{\circ}$.Horizontal component: $u_x = u \cos(45^{\circ}) = 19.6 \sqrt{2} 	imes \frac{1}{\sqrt{2}} = 19.6 \ m/s$.Vertical component: $u_y = u \sin(45^{\circ}) = 19.6 \sqrt{2} 	imes \frac{1}{\sqrt{2}} = 19.6 \ m/s$.After time $t = 2 \ s$,the horizontal velocity remains constant: $v_x = u_x = 19.6 \ m/s$.The vertical velocity is given by $v_y = u_y - gt = 19.6 - (9.8 	imes 2) = 19.6 - 19.6 = 0 \ m/s$.Since the vertical component of velocity is $0 \ m/s$,the velocity vector is purely horizontal.Therefore,the angle $\alpha$ with the horizontal is $0^{\circ}$.

$A$ piece of marble is projected from the Earth's surface with a velocity of $19.6 \sqrt{2} \ m/s$ at an angle of $45^{\circ}$. $2 \ s$ later,its velocity makes an angle $\alpha$ with the horizontal,where $\alpha$ is $..........$ (in $^{\circ}$)

Similar Questions

$A$ body is projected at an angle $\theta$ with the horizontal. Another body is projected with the same speed at an angle $\theta$ with the vertical. The ratio of their maximum heights is:

$A$ ball is projected horizontally with a velocity of $5 \text{ m/s}$ from the top of a building $19.6 \text{ m}$ high. How long will the ball take to hit the ground?

$A$ particle aimed at a target, projected with an angle $15^{\circ}$ with the horizontal is short of the target by $10 \ m$. If projected with an angle of $45^{\circ}$ it is away from the target by $10 \ m$, then the angle of projection to hit the target is

Four projectiles are fired with the same velocities at angles $25^{\circ}, 40^{\circ}, 55^{\circ}$ and $70^{\circ}$ with the horizontal. The range of the projectile will be largest for the one projected at angle $.......$ . (in $^{\circ}$)

$A$ particle is projected with a velocity $v$ such that its horizontal range is twice the greatest height attained. The horizontal range is

Vedclass Test Series

Exam Paper Generator

Online Exam Module