A pineapple costs Rs. 7 each. A watermelon co | vedclass

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Question

(C) Let the number of pineapples be $x$ and the number of watermelons be $y$.Given that the cost of one pineapple is $Rs. 7$ and one watermelon is $Rs

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) Let the number of pineapples be $x$ and the number of watermelons be $y$.Given that the cost of one pineapple is $Rs. 7$ and one watermelon is $Rs. 5$.The total expenditure is $Rs. 38$.Therefore,the linear equation is $7x + 5y = 38$,where $x$ and $y$ must be non-negative integers.If $y = 1$,$7x = 38 - 5 = 33$ (not divisible by $7$).If $y = 2$,$7x = 38 - 10 = 28 \Rightarrow x = 4$.If $y = 3$,$7x = 38 - 15 = 23$ (not divisible by $7$).If $y = 4$,$7x = 38 - 20 = 18$ (not divisible by $7$).If $y = 5$,$7x = 38 - 25 = 13$ (not divisible by $7$).If $y = 6$,$7x = 38 - 30 = 8$ (not divisible by $7$).If $y = 7$,$7x = 38 - 35 = 3$ (not divisible by $7$).Thus,the only integer solution is $x = 4$ and $y = 2$.Hence,the number of watermelons purchased is $2$.

$A$ pineapple costs $Rs. 7$ each. $A$ watermelon costs $Rs. 5$ each. $X$ spends $Rs. 38$ on these fruits. The number of watermelons purchased is

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