If sqrt{1+frac{x}{144}}=frac{13}{12}, then x | vedclass

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Question

(D) Given the equation: $\sqrt{1+\frac{x}{144}} = \frac{13}{12}$Square both sides of the equation to remove the square root:$1 + \frac{x}{144} = \left

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(D) Given the equation: $\sqrt{1+\frac{x}{144}} = \frac{13}{12}$Square both sides of the equation to remove the square root:$1 + \frac{x}{144} = \left(\frac{13}{12}\right)^2$$1 + \frac{x}{144} = \frac{169}{144}$Subtract $1$ from both sides:$\frac{x}{144} = \frac{169}{144} - 1$$\frac{x}{144} = \frac{169 - 144}{144}$$\frac{x}{144} = \frac{25}{144}$Multiplying both sides by $144$,we get:$x = 25$

If $\sqrt{1+\frac{x}{144}}=\frac{13}{12},$ then $x$ equals to

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