If m^{n} = 169,what is the value of (m+1)(n-1 | vedclass

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Question

(A) Given the equation $m^{n} = 169$.We know that $169 = 13^{2}$.Comparing $m^{n} = 13^{2}$,we get two possible cases:Case $1$: $m = 13$ and $n = 2$.C

Vedclass · Accepted Answer

$14$

Vedclass · Answer

(A) Given the equation $m^{n} = 169$.We know that $169 = 13^{2}$.Comparing $m^{n} = 13^{2}$,we get two possible cases:Case $1$: $m = 13$ and $n = 2$.Case $2$: $m = -13$ and $n = 2$ (since $(-13)^{2} = 169$).For Case $1$ $(m = 13, n = 2)$:$(m+1)(n-1) = (13+1)(2-1) = 14 	imes 1 = 14$.For Case $2$ $(m = -13, n = 2)$:$(m+1)(n-1) = (-13+1)(2-1) = -12 	imes 1 = -12$.Since $14$ is the only option provided,the correct answer is $14$.

If $m^{n} = 169$,what is the value of $(m+1)(n-1)$?

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