If left(-frac{1}{2}right) times (x - 5) + 3 = | vedclass

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(A) Given the equation: $\left(-\frac{1}{2}ight) 	imes (x - 5) + 3 = -\frac{5}{2}$Subtract $3$ from both sides:$\left(-\frac{1}{2}ight) 	imes (x

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(A) Given the equation: $\left(-\frac{1}{2}ight) 	imes (x - 5) + 3 = -\frac{5}{2}$Subtract $3$ from both sides:$\left(-\frac{1}{2}ight) 	imes (x - 5) = -\frac{5}{2} - 3$$\left(-\frac{1}{2}ight) 	imes (x - 5) = -\frac{5}{2} - \frac{6}{2}$$\left(-\frac{1}{2}ight) 	imes (x - 5) = -\frac{11}{2}$Multiply both sides by $-2$:$x - 5 = \left(-\frac{11}{2}ight) 	imes (-2)$$x - 5 = 11$Add $5$ to both sides:$x = 11 + 5$$x = 16$

If $\left(-\frac{1}{2}\right) \times (x - 5) + 3 = -\frac{5}{2}$,then what is the value of $x$?

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