$A$ point particle of mass $0.1\, kg$ is executing $S.H.M.$ with an amplitude of $0.1\, m$. When the particle passes through the mean position,its kinetic energy is $8 \times 10^{-3} \, J$. Obtain the equation of motion of this particle if the initial phase of oscillation is $45^o$.

  • A
    $y = 0.1 \sin (\pm 4t + \pi/4)$
  • B
    $y = 0.2 \sin (\pm 4t + \pi/4)$
  • C
    $y = 0.1 \sin (\pm 2t + \pi/4)$
  • D
    $y = 0.2 \sin (\pm 2t + \pi/4)$

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