A polaroid is placed at 45^{circ} to an incom | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Malus's Law,the intensity of light transmitted through a polarizer is given by the formula:$I = I_0 \cos^2 	heta$where $I_0$ is the

Vedclass · Accepted Answer

$I_0/2$

Vedclass · Answer

(B) According to Malus's Law,the intensity of light transmitted through a polarizer is given by the formula:$I = I_0 \cos^2 	heta$where $I_0$ is the intensity of the incident linearly polarized light,$	heta$ is the angle between the transmission axis of the polarizer and the plane of polarization of the incident light,and $I$ is the transmitted intensity.Given that $	heta = 45^{\circ}$:$I = I_0 \cos^2(45^{\circ})$Since $\cos(45^{\circ}) = \frac{1}{\sqrt{2}}$,we have:$I = I_0 \left(\frac{1}{\sqrt{2}}ight)^2$$I = I_0 \left(\frac{1}{2}ight)$$I = \frac{I_0}{2}$

$A$ polaroid is placed at $45^{\circ}$ to an incoming linearly polarized light of intensity $I_0$. The intensity of light passing through the polaroid after polarization will be:

Similar Questions

In the case of linearly polarized light,the magnitude of the electric field vector:

When light is incident on a doubly refracting crystal,two refracted rays-ordinary ray ($O$-ray) and extraordinary ray ($E$-ray) are produced. Then:

Which of the following is a biaxial crystal?

In a system of two crossed polarisers,it is found that the intensity of light from the second polariser is half of that from the first polariser. The angle between their pass axes is (in $^{\circ}$)

Light waves can be polarized if they are...

Vedclass Test Series

Exam Paper Generator

Online Exam Module