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(B) Input voltage,$V_1 = 2300\; V$.Number of turns in the primary coil,$n_1 = 4000$.Output voltage,$V_2 = 230\; V$.Let the number of turns in the seco

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$400$

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(B) Input voltage,$V_1 = 2300\; V$.Number of turns in the primary coil,$n_1 = 4000$.Output voltage,$V_2 = 230\; V$.Let the number of turns in the secondary coil be $n_2$.The relationship between voltage and the number of turns in a transformer is given by the formula:$\frac{V_1}{V_2} = \frac{n_1}{n_2}$Substituting the given values:$\frac{2300}{230} = \frac{4000}{n_2}$$10 = \frac{4000}{n_2}$$n_2 = \frac{4000}{10} = 400$.Thus,the number of turns in the secondary coil should be $400$.

$A$ power transmission line feeds input power at $2300\; V$ to a step-down transformer with its primary windings having $4000$ turns. What should be the number of turns in the secondary in order to get output power at $230\; V$?

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