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(B) According to Avogadro's Law,at the same temperature and pressure,equal volumes of gases contain an equal number of moles.Since the volume of the v

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$\frac{1}{2}$ that of $SO_2$

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(B) According to Avogadro's Law,at the same temperature and pressure,equal volumes of gases contain an equal number of moles.Since the volume of the vessel is constant,the number of moles of $O_2$ and $SO_2$ will be the same.Weight of gas = $	ext{Number of moles} 	imes 	ext{Molar mass}$.Since the number of moles is the same,the weight of the gas is directly proportional to its molar mass.Weight of $O_2$ / Weight of $SO_2$ = $\frac{	ext{Molar mass of } O_2}{	ext{Molar mass of } SO_2} = \frac{32}{64} = \frac{1}{2}$.Therefore,the weight of oxygen will be $\frac{1}{2}$ that of $SO_2$.

$A$ pre-weighed vessel was filled with oxygen at $N.T.P.$ and weighed. It was then evacuated,filled with $SO_2$ at the same temperature and pressure,and again weighed. The weight of oxygen will be

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