A public park,in the form of a square,has an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the side length of the square park be $l$. The area of a square is given by $A = l^2$.Given $A = 100 \; m^2$,we have $l = \sqrt{100} = 10 \; m

Vedclass · Accepted Answer

$(10 \pm 0.01)$

Vedclass · Answer

(A) Let the side length of the square park be $l$. The area of a square is given by $A = l^2$.Given $A = 100 \; m^2$,we have $l = \sqrt{100} = 10 \; m$.The relative error in area is related to the relative error in length by the formula $\frac{\Delta A}{A} = 2 \frac{\Delta l}{l}$.Substituting the given values,$\frac{0.2}{100} = 2 \frac{\Delta l}{10}$.Solving for $\Delta l$: $\Delta l = \frac{0.2 	imes 10}{100 	imes 2} = \frac{2}{200} = 0.01 \; m$.Thus,the side of the park is $(10 \pm 0.01) \; m$.

$A$ public park,in the form of a square,has an area of $(100 \pm 0.2) \; m^2$. The side of the park is ............ $m$.

Similar Questions

The incentre of the triangle formed by the lines $x+y=1$,$x=1$,and $y=1$ is

Which pair of oxides is acidic in nature?

Heterosis is . . . . . . .

The equation of the image of the circle $x^2 + y^2 + 16x - 24y + 183 = 0$ by the line mirror $4x + 7y + 13 = 0$ is

$A$ progressive wave of frequency $50 ~Hz$ is travelling with velocity $350 ~m/s$ through a medium. The change in phase at a given time interval of $0.01 ~s$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module