A ray of light passes through four transparen | vedclass

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(D) According to Snell's law for multiple parallel interfaces,the product of the refractive index and the sine of the angle of incidence at each inter

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$\mu_4 = \mu_1$

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(D) According to Snell's law for multiple parallel interfaces,the product of the refractive index and the sine of the angle of incidence at each interface remains constant.Let $	heta_1$ be the angle of incidence in the first medium and $	heta_4$ be the angle of refraction in the fourth medium.Applying Snell's law at each interface:$\mu_1 \sin 	heta_1 = \mu_2 \sin 	heta_2 = \mu_3 \sin 	heta_3 = \mu_4 \sin 	heta_4$.Since the emergent ray $CD$ is parallel to the incident ray $AB$,the angle of incidence $	heta_1$ must be equal to the angle of emergence $	heta_4$ (i.e.,$	heta_1 = 	heta_4$).Substituting this into the equation,we get $\mu_1 \sin 	heta_1 = \mu_4 \sin 	heta_1$.Therefore,$\mu_1 = \mu_4$.

$A$ ray of light passes through four transparent media with refractive indices $\mu_1, \mu_2, \mu_3$ and $\mu_4$ as shown in the figure. The surfaces of all media are parallel. If the emergent ray $CD$ is parallel to the incident ray $AB$,we must have

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