A ray of light travelling in a transparent me | vedclass

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(D) For total internal reflection $(TIR)$ to occur,the angle of incidence $(i)$ must be greater than the critical angle $(C)$.$i > C$Taking the sine o

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Both $(b)$ and $(c)$

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(D) For total internal reflection $(TIR)$ to occur,the angle of incidence $(i)$ must be greater than the critical angle $(C)$.$i > C$Taking the sine of both sides,we get $\sin i > \sin C$.Given $i = 45^\circ$,we have $\sin 45^\circ > \frac{1}{n}$.Since $\sin 45^\circ = \frac{1}{\sqrt{2}}$,the inequality becomes $\frac{1}{\sqrt{2}} > \frac{1}{n}$.This implies $n > \sqrt{2}$.Since $\sqrt{2} \approx 1.414$,we require $n > 1.414$.Comparing this with the given options:Option $(a)$ $1.3 Option $(b)$ $1.6 > 1.414$ (Correct).Option $(c)$ $1.5 > 1.414$ (Correct).Therefore,both $(b)$ and $(c)$ are possible values for $n$.

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