A reaction of benzonitrile with one equivalen | vedclass

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(D) The reaction of benzonitrile $(C_{6}H_{5}CN)$ with one equivalent of methylmagnesium bromide $(CH_{3}MgBr)$ followed by acid hydrolysis $(H_{3}O^{

Vedclass · Accepted Answer

Iodoform test

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(D) The reaction of benzonitrile $(C_{6}H_{5}CN)$ with one equivalent of methylmagnesium bromide $(CH_{3}MgBr)$ followed by acid hydrolysis $(H_{3}O^{+})$ proceeds as follows:$1$. Nucleophilic attack of $CH_{3}^{-}$ on the carbon of the nitrile group forms an imine magnesium salt intermediate: $C_{6}H_{5}C(CH_{3})=NMgBr$.$2$. Hydrolysis of this intermediate yields acetophenone $(C_{6}H_{5}COCH_{3})$ and ammonia $(NH_{3})$.$3$. Acetophenone contains the acetyl group $(CH_{3}CO-)$ attached to a phenyl ring. Compounds containing the $CH_{3}CO-$ group attached to a hydrogen or carbon atom give a positive iodoform test with $I_{2}/NaOH$.

$A$ reaction of benzonitrile with one equivalent of $CH_{3}MgBr$ followed by hydrolysis produces a yellow liquid $P$. The compound $P$ will give a positive result for which of the following tests?

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