The reaction of C_6H_5CH=CHCHO with LiAlH_4 g | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $LiAlH_4$ (Lithium aluminium hydride) is a strong reducing agent that reduces both the aldehyde group $(-CHO)$ and the carbon-carbon double bond $

Vedclass · Accepted Answer

$C_6H_5CH_2CH_2CH_2OH$

Vedclass · Answer

(A) $LiAlH_4$ (Lithium aluminium hydride) is a strong reducing agent that reduces both the aldehyde group $(-CHO)$ and the carbon-carbon double bond $(C=C)$ when conjugated with an aromatic ring or an electron-withdrawing group. In the case of cinnamaldehyde $(C_6H_5CH=CHCHO)$,$LiAlH_4$ reduces both the aldehyde group to a primary alcohol and the double bond to a single bond,resulting in the formation of $3-phenylpropan-1-ol$ $(C_6H_5CH_2CH_2CH_2OH)$.

The reaction of $C_6H_5CH=CHCHO$ with $LiAlH_4$ gives

Similar Questions

Which pair never represents $X$ and $Y$ in the following reaction?
Reaction: $X \xrightarrow{Y} CHCl_3 + Z$

The major products $A$ and $B$ for the following reactions are,respectively:

Consider the given reaction,the product $A$ is :

The major product of the following reaction is:

Which of the following is used to detect aldehydes?

Vedclass Test Series

Exam Paper Generator

Online Exam Module