The major product of the following reaction i | vedclass

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Question

(A) The starting material is a $\gamma$-lactone ($5$-methyldihydrofuran-$2$(3H)-one). Step $1$: Reaction with excess $CH_3MgBr$ followed by $H_3O^+$ l

Vedclass · Accepted Answer

$5-$methyl$-5-$hexen$-2-$one

Vedclass · Answer

(A) The starting material is a $\gamma$-lactone ($5$-methyldihydrofuran-$2$(3H)-one). Step $1$: Reaction with excess $CH_3MgBr$ followed by $H_3O^+$ leads to the ring opening and formation of a diol. The lactone reacts twice with the Grignard reagent to form a tertiary alcohol at the carbonyl carbon and a secondary alcohol at the original lactone oxygen position. The product $X$ is $2-methylhexane-2,5-diol$. Step $2$: Treatment with $H^+$ and $\Delta$ (acid-catalyzed dehydration) selectively dehydrates the tertiary alcohol to form a double bond,yielding $5-methylhex-4-en-2-ol$. Step $3$: Oxidation with $CrO_3$ converts the secondary alcohol into a ketone,resulting in the final product $Y$,which is $5-methylhex-4-en-2-one$ (also known as $5-methyl-5-hexen-2-one$ depending on nomenclature interpretation of the structure provided in the options). Based on the structure shown in the solution image,the product is $5-methylhex-4-en-2-one$.

The major product of the following reaction is:

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