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(A) According to the Law of Floatation,a floating object displaces a weight of liquid equal to its own weight.Since the weight of the block remains co

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(A) According to the Law of Floatation,a floating object displaces a weight of liquid equal to its own weight.Since the weight of the block remains constant,the weight of the displaced water must also remain constant.Because the weight of the displaced water is equal to the product of the volume of displaced water,the density of water,and the acceleration due to gravity $(W = V_{disp} \cdot \rho_{water} \cdot g)$,and both the density of water and gravity are constant,the volume of displaced water $(V_{disp})$ must remain constant.Since the volume of displaced water does not change,the level of water in the container remains unchanged.

$A$ rectangular block is $5 \ cm \times 5 \ cm \times 10 \ cm$ in size. The block is floating in water with the $5 \ cm$ side vertical. If it floats with the $10 \ cm$ side vertical,what change will occur in the level of water?

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