$A$ resistance $R$ draws power $P$ when connected to an $AC$ source. If an inductance is now placed in series with the resistance,such that the impedance of the circuit becomes $Z$,the power drawn will be

  • A
    $P \left( \frac{R}{Z} \right)^2$
  • B
    $P \sqrt{\frac{R}{Z}}$
  • C
    $P \left( \frac{R}{Z} \right)$
  • D
    $P$

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