In an LR circuit,the value of L is (frac{0.3} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given: Inductance $L = \frac{0.3}{\pi} \ H$,Resistance $R = 40 \ \Omega$,Voltage $V = 230 \ V$,Frequency $f = 50 \ Hz$.First,calculate the inducti

Vedclass · Accepted Answer

$50 \ \Omega, 4.6 \ A$

Vedclass · Answer

(D) Given: Inductance $L = \frac{0.3}{\pi} \ H$,Resistance $R = 40 \ \Omega$,Voltage $V = 230 \ V$,Frequency $f = 50 \ Hz$.First,calculate the inductive reactance $X_L = 2\pi f L$.$X_L = 2 	imes \pi 	imes 50 	imes \frac{0.3}{\pi} = 100 	imes 0.3 = 30 \ \Omega$.The impedance $Z$ of the $LR$ circuit is given by $Z = \sqrt{R^2 + X_L^2}$.$Z = \sqrt{40^2 + 30^2} = \sqrt{1600 + 900} = \sqrt{2500} = 50 \ \Omega$.The current $I$ in the circuit is given by $I = \frac{V}{Z}$.$I = \frac{230}{50} = 4.6 \ A$.Thus,the impedance is $50 \ \Omega$ and the current is $4.6 \ A$.

In an $LR$ circuit,the value of $L$ is $(\frac{0.3}{\pi}) \ H$ and the value of $R$ is $40 \ \Omega$. If an alternating e.m.f. of $230 \ V$ at $50 \ Hz$ is connected to the circuit,what are the impedance and the current in the circuit,respectively?

Similar Questions

$A$ resistance $R$ draws power $P$ when connected to an $AC$ source. If an inductance is now placed in series with the resistance,such that the impedance of the circuit becomes $Z$,the power drawn will be

$A$ coil of inductance $0.50 \; H$ and resistance $100 \; \Omega$ is connected to a $240 \; V, 50 \; Hz$ $AC$ supply.
$(a)$ What is the maximum current in the coil?
$(b)$ What is the time lag between the voltage maximum and the current maximum?

$A$ bulb and a capacitor are connected in series to a source of alternating current. If its frequency is increased,while keeping the voltage of the source constant,then

In a $L-R$ circuit of $4 \text{ mH}$ inductance and $3 \text{ } \Omega$ resistance, e.m.f. $E = \cos(1000t) \text{ V}$ is applied. The amplitude of current is (in $\text{ A}$)

$A$ coil of inductive reactance $ \frac{1}{\sqrt{3}} \Omega $ and resistance $ 1 \Omega $ is connected to a $ 200 \ V, 50 \ Hz $ $AC$ supply. The time lag between maximum voltage and current is

Vedclass Test Series

Exam Paper Generator

Online Exam Module