$A$ resonant $AC$ circuit contains a capacitor of capacitance $10^{-6} \ F$ and an inductor of $10^{-4} \ H$. The frequency of electrical oscillations will be:

In the circuit given below,the capacitor $C$ is charged by closing the switch $S_1$ and opening the switch $S_2$. After charging,the switch $S_1$ is opened and $S_2$ is closed. Find the maximum current in the circuit.

$A$ $1 \mu F$ capacitor is charged to $50 \ V$ and is then discharged through a $10 \ mH$ inductor of negligible resistance. The maximum current in the inductor is (in $A$)

$A$ capacitor of capacity $C$ is charged to a potential difference of $V_1$. The plates of the capacitor are then connected to an ideal inductor of inductance $L$. The current through the inductor when the potential difference across the capacitor reduces to $V_2$ is

$A$ capacitor is fully charged with a battery. Then the battery is removed and a coil is connected with the capacitor in parallel. How does the current vary?

$A$ $2\,\mu F$ capacitor is charged to $100\,V$. After disconnecting the battery,a $20\,mH$ coil is connected across the charged capacitor. The capacitor discharges through the inductor and the current in the circuit is oscillatory. Assuming the resistance of the coil is zero,the maximum current in the circuit is.....$A$