A right triangle ABC with sides 5 , cm, 12 , | vedclass

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(C) $1$. When the triangle is revolved about the side $12 \, cm$:Height $(h) = 12 \, cm$,Radius $(r) = 5 \, cm$.Volume $V_1 = \frac{1}{3} \pi r^2 h =

Vedclass · Accepted Answer

$5:12$

Vedclass · Answer

(C) $1$. When the triangle is revolved about the side $12 \, cm$:Height $(h) = 12 \, cm$,Radius $(r) = 5 \, cm$.Volume $V_1 = \frac{1}{3} \pi r^2 h = \frac{1}{3} 	imes \pi 	imes (5)^2 	imes 12 = 100 \pi \, cm^3$.$2$. When the triangle is revolved about the side $5 \, cm$:Height $(h) = 5 \, cm$,Radius $(r) = 12 \, cm$.Volume $V_2 = \frac{1}{3} \pi r^2 h = \frac{1}{3} 	imes \pi 	imes (12)^2 	imes 5 = 240 \pi \, cm^3$.$3$. Ratio of the volumes:Ratio $= \frac{V_1}{V_2} = \frac{100 \pi}{240 \pi} = \frac{100}{240} = \frac{5}{12} = 5:12$.

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