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(A) Since the tank is rigid, the volume $V$ remains constant. According to Gay-Lussac's Law, for a fixed amount of gas at constant volume, the pressur

Vedclass · Accepted Answer

$32$

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(A) Since the tank is rigid, the volume $V$ remains constant. According to Gay-Lussac's Law, for a fixed amount of gas at constant volume, the pressure is directly proportional to the absolute temperature: $\frac{P_1}{T_1} = \frac{P_2}{T_2}$.Given:$P_1 = 30 \ atm$$T_1 = 27^{\circ} C = 27 + 273 = 300 \ K$$T_2 = 45^{\circ} C = 45 + 273 = 318 \ K$Substituting the values into the equation:$\frac{30}{300} = \frac{P_2}{318}$$0.1 = \frac{P_2}{318}$$P_2 = 0.1 	imes 318 = 31.8 \ atm$.Rounding to the nearest integer, we get $P_2 = 32 \ atm$.

$A$ rigid nitrogen tank stored inside a laboratory has a pressure of $30 \ atm$ at $06:00 \ am$ when the temperature is $27^{\circ} C$. At $03:00 \ pm$, when the temperature is $45^{\circ} C$, the pressure in the tank will be $...... \ atm.$ [nearest integer]

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