A river 10,m deep is flowing at 5,m/s. The sh | vedclass

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(C) The shearing stress $	au$ is given by the formula: $	au = \eta \frac{dv}{dy}$.Here,$\eta = 10^{-3}\,SI\,unit$ is the coefficient of viscosity.Th

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$0.5	imes 10^{-3}\,N/m^2$

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(C) The shearing stress $	au$ is given by the formula: $	au = \eta \frac{dv}{dy}$.Here,$\eta = 10^{-3}\,SI\,unit$ is the coefficient of viscosity.The velocity gradient $\frac{dv}{dy}$ can be approximated as $\frac{v}{h}$,where $v = 5\,m/s$ is the velocity and $h = 10\,m$ is the depth of the river.Substituting the values:$	au = 10^{-3} 	imes \frac{5}{10}$$	au = 10^{-3} 	imes 0.5$$	au = 0.5 	imes 10^{-3}\,N/m^2$.

$A$ river $10\,m$ deep is flowing at $5\,m/s$. The shearing stress between horizontal layers of the river is :- $(\eta = 10^{-3}\,SI\,unit)$

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