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(B) Volume of the rod $V = 10 	imes 0.5 	imes 0.2 \, cm^3 = 1 \, cm^3 = 10^{-6} \, m^3$.Given magnetic field strength $H = 0.5 	imes 10^4 \, Am^{-1

Vedclass · Accepted Answer

$6.28$

Vedclass · Answer

(B) Volume of the rod $V = 10 	imes 0.5 	imes 0.2 \, cm^3 = 1 \, cm^3 = 10^{-6} \, m^3$.Given magnetic field strength $H = 0.5 	imes 10^4 \, Am^{-1}$ and magnetic moment $M = 5 \, Am^2$.Intensity of magnetization $I = \frac{M}{V} = \frac{5}{10^{-6}} = 5 	imes 10^6 \, Am^{-1}$.Magnetic induction $B$ is given by $B = \mu_0(I + H)$.Since $I \gg H$,we have $B \approx \mu_0 I$.$B = 4\pi 	imes 10^{-7} 	imes 5 	imes 10^6 = 20\pi 	imes 10^{-1} = 2\pi \approx 6.28 \, T$.

$A$ rod of ferromagnetic material with dimensions $10 \, cm \times 0.5 \, cm \times 0.2 \, cm$ is placed in a magnetic field of strength $0.5 \times 10^4 \, Am^{-1}$. As a result,a magnetic moment of $5 \, Am^2$ is produced in the rod. The value of magnetic induction will be.... $T$

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