A room is 4, m, 37, cm long and 3, m, 23, cm | vedclass

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(C) Length of the room $= 4\, m\, 37\, cm = 437\, cm$.Breadth of the room $= 3\, m\, 23\, cm = 323\, cm$.To find the minimum number of square slabs,th

Vedclass · Accepted Answer

$391$

Vedclass · Answer

(C) Length of the room $= 4\, m\, 37\, cm = 437\, cm$.Breadth of the room $= 3\, m\, 23\, cm = 323\, cm$.To find the minimum number of square slabs,the side of each square slab must be the $H.C.F.$ of the length and breadth of the room.$H.C.F.$ of $437$ and $323$:$437 = 19 	imes 23$$323 = 19 	imes 17$Thus,$H.C.F. = 19\, cm$.The side of the square slab is $19\, cm$.Number of slabs $= \frac{	ext{Area of the room}}{	ext{Area of one slab}} = \frac{437 	imes 323}{19 	imes 19}$.Number of slabs $= 23 	imes 17 = 391$.

$A$ room is $4\, m\, 37\, cm$ long and $3\, m\, 23\, cm$ broad. It is required to pave the floor with minimum square slabs. Find the number of slabs required for this purpose.

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