A school has five houses A, B, C, D and E. A | vedclass

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(D) Total number of students $= 23$.Number of students in houses $A, B$,and $C = 4 + 8 + 5 = 17$.Number of students not in houses $A, B$,or $C$ (i.e.,

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$6$

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(D) Total number of students $= 23$.Number of students in houses $A, B$,and $C = 4 + 8 + 5 = 17$.Number of students not in houses $A, B$,or $C$ (i.e.,from houses $D$ and $E$) $= 23 - 17 = 6$.Alternatively,students from house $D = 2$,and students from house $E = 23 - (4 + 8 + 5 + 2) = 23 - 19 = 4$. Total $= 2 + 4 = 6$.The probability that the selected student is not from $A, B$,or $C = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{6}{23}$.

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