A series combination of n_1 capacitors,each o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For the series combination of $n_1$ capacitors of capacitance $C_1$ connected to a $4V$ source:The equivalent capacitance is $C_s = \frac{C_1}{n_1

Vedclass · Accepted Answer

$\frac{16C_1}{n_1n_2}$

Vedclass · Answer

(D) For the series combination of $n_1$ capacitors of capacitance $C_1$ connected to a $4V$ source:The equivalent capacitance is $C_s = \frac{C_1}{n_1}$.The total energy stored is $U_s = \frac{1}{2} C_s (4V)^2 = \frac{1}{2} \left(\frac{C_1}{n_1}\right) (16V^2) = \frac{8C_1V^2}{n_1}$.For the parallel combination of $n_2$ capacitors of capacitance $C_2$ connected to a $V$ source:The equivalent capacitance is $C_p = n_2 C_2$.The total energy stored is $U_p = \frac{1}{2} C_p V^2 = \frac{1}{2} (n_2 C_2) V^2$.Given that $U_s = U_p$,we equate the two expressions:$\frac{8C_1V^2}{n_1} = \frac{1}{2} n_2 C_2 V^2$.Simplifying for $C_2$:$C_2 = \frac{16C_1}{n_1n_2}$.

Similar Questions

Calculate the amount of heat liberated in the circuit after closing the switch $S$.

Each plate of a parallel plate capacitor has a charge $q$ on it. The capacitor is now connected to a battery. Now,

For the given circuit,find the potential at point $a$. (in $V$)

$A$ soap bubble is given a negative charge,then its radius

Vedclass Test Series

Exam Paper Generator

Online Exam Module