$A$ short bar magnet with its north pole facing north forms a neutral point at $P$ in the horizontal plane. If the magnet is rotated by $90^o$ in the horizontal plane,the net magnetic induction at $P$ is (Horizontal component of earth's magnetic field = $B_H$)

  • A
    $0$
  • B
    $2 B_H$
  • C
    $\frac{\sqrt{5}}{2} B_H$
  • D
    $\sqrt{5} B_H$

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