A shot-put is a metallic sphere of radius 4.9 | vedclass

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(B) The shot-put is a solid sphere. The mass of the sphere is calculated by multiplying its volume by its density.Step $1$: Calculate the volume of th

Vedclass · Accepted Answer

$3.85$

Vedclass · Answer

(B) The shot-put is a solid sphere. The mass of the sphere is calculated by multiplying its volume by its density.Step $1$: Calculate the volume of the sphere.The formula for the volume of a sphere is $V = \frac{4}{3} \pi r^3$.Given $r = 4.9 \, cm$,we have:$V = \frac{4}{3} 	imes \frac{22}{7} 	imes (4.9)^3$$V = \frac{4}{3} 	imes \frac{22}{7} 	imes 4.9 	imes 4.9 	imes 4.9$$V = \frac{4}{3} 	imes 22 	imes 0.7 	imes 4.9 	imes 4.9$$V \approx 493.0 \, cm^3$.Step $2$: Calculate the mass of the shot-put.Mass = Volume $	imes$ DensityMass = $493.0 \, cm^3 	imes 7.8 \, g/cm^3$Mass = $3845.4 \, g$.Step $3$: Convert the mass into kilograms.Since $1 \, kg = 1000 \, g$,Mass = $\frac{3845.4}{1000} \, kg \approx 3.85 \, kg$.

$A$ shot-put is a metallic sphere of radius $4.9 \, cm$. If the density of the metal is $7.8 \, g/cm^3$,find the mass of the shot-put. (in $, kg$)

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