A silver wire has a resistance of 2.1; Omega | vedclass

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Question

(A) Given:Initial temperature,$T_{1} = 27.5^{\circ} C$Resistance at $T_{1}$,$R_{1} = 2.1\; \Omega$Final temperature,$T_{2} = 100^{\circ} C$Resistance

Vedclass · Accepted Answer

$0.0039^{\circ} C^{-1}$

Vedclass · Answer

(A) Given:Initial temperature,$T_{1} = 27.5^{\circ} C$Resistance at $T_{1}$,$R_{1} = 2.1\; \Omega$Final temperature,$T_{2} = 100^{\circ} C$Resistance at $T_{2}$,$R_{2} = 2.7\; \Omega$The temperature coefficient of resistivity $\alpha$ is given by the formula:$\alpha = \frac{R_{2} - R_{1}}{R_{1}(T_{2} - T_{1})}$Substituting the values:$\alpha = \frac{2.7 - 2.1}{2.1(100 - 27.5)}$$\alpha = \frac{0.6}{2.1 	imes 72.5}$$\alpha = \frac{0.6}{152.25}$$\alpha \approx 0.0039^{\circ} C^{-1}$

$A$ silver wire has a resistance of $2.1\; \Omega$ at $27.5^{\circ} C$ and a resistance of $2.7\; \Omega$ at $100^{\circ} C$. Determine the temperature coefficient of resistivity of silver.

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