A simple pendulum of frequency f has a metal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The frequency of a simple pendulum is given by $f = \frac{1}{2\pi} \sqrt{\frac{g_{eff}}{L}}$.When a negatively charged bob oscillates above a larg

Vedclass · Accepted Answer

more than $f$

Vedclass · Answer

(C) The frequency of a simple pendulum is given by $f = \frac{1}{2\pi} \sqrt{\frac{g_{eff}}{L}}$.When a negatively charged bob oscillates above a large positively charged plate,it experiences an additional downward electrostatic force $F_e$ towards the plate.This force acts in the same direction as gravity,effectively increasing the acceleration due to gravity.Thus,$g_{eff} = g + \frac{F_e}{m}$,where $m$ is the mass of the bob.Since $g_{eff} > g$,the frequency $f$ increases.Therefore,the new frequency will be more than $f$.

$A$ simple pendulum of frequency $f$ has a metal bob. If the bob is charged negatively and is allowed to oscillate above a large positively charged plate,the frequency will be:

Similar Questions

$A$ pendulum clock is set to give correct time at sea level. This clock is moved to a hill station at an altitude of $2500 \ m$ above sea level. In order to keep correct time at the hill station,the length of the pendulum:

$A$ pendulum is swinging in an elevator. Its period will be greatest when the elevator is

The bob of a pendulum of length $l$ is pulled aside from its equilibrium position through an angle $\theta$ and then released. The bob will then pass through its equilibrium position with speed $v$,where $v$ equals

The time period of a simple pendulum measured inside a stationary lift is found to be $T$. If the lift starts accelerating upwards with an acceleration $g/3$,the new time period is:

$A$ simple pendulum has a time period $t$. Its time period in a lift which is moving upwards with an acceleration of $3 \ m/s^2$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module