The bob of a pendulum of length l is pulled a | vedclass

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(C) When the pendulum bob is pulled aside by an angle $	heta$,it is raised to a vertical height $h$ above its equilibrium position.From the geometry

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$\sqrt{2gl(1 - \cos 	heta)}$

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(C) When the pendulum bob is pulled aside by an angle $	heta$,it is raised to a vertical height $h$ above its equilibrium position.From the geometry of the pendulum,the vertical height $h$ is given by $h = l - l \cos 	heta = l(1 - \cos 	heta)$.According to the law of conservation of mechanical energy,the potential energy at the highest point is converted into kinetic energy at the equilibrium position.$PE_{initial} = KE_{final}$$Mgh = \frac{1}{2} Mv^2$Substituting $h = l(1 - \cos 	heta)$:$Mg l(1 - \cos 	heta) = \frac{1}{2} Mv^2$$v^2 = 2gl(1 - \cos 	heta)$$v = \sqrt{2gl(1 - \cos 	heta)}$

The bob of a pendulum of length $l$ is pulled aside from its equilibrium position through an angle $\theta$ and then released. The bob will then pass through its equilibrium position with speed $v$,where $v$ equals

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