$A$ simple pendulum with a bob of mass $m$ oscillates from $A$ to $C$ and back to $A$ such that $PB$ is $H$. If the acceleration due to gravity is $g$,then the velocity of the bob as it passes through $B$ is

  • A
    $mgH$
  • B
    $\sqrt{2gH}$
  • C
    $\sqrt{gH}$
  • D
    Zero

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