A small satellite is revolving near the Earth | vedclass

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(A) The orbital velocity $(v_{0})$ of a satellite revolving near the Earth's surface is given by the formula:$v_{0} = \sqrt{g R_{e}}$Where $g$ is the

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(A) The orbital velocity $(v_{0})$ of a satellite revolving near the Earth's surface is given by the formula:$v_{0} = \sqrt{g R_{e}}$Where $g$ is the acceleration due to gravity $(9.8 \ m/s^{2})$ and $R_{e}$ is the radius of the Earth $(6.4 	imes 10^{6} \ m)$.Substituting the values:$v_{0} = \sqrt{9.8 	imes 6.4 	imes 10^{6}}$$v_{0} = \sqrt{62.72 	imes 10^{6}}$$v_{0} \approx 7.92 	imes 10^{3} \ m/s$Converting to $km/s$:$v_{0} \approx 7.92 \ km/s \approx 8 \ km/s$.Thus,the correct option is $A$.

$A$ small satellite is revolving near the Earth's surface. Its orbital velocity will be nearly......... $km/sec$.

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