A solenoid of length 0.5 ,m has a radius of 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnetic field $B$ inside a long solenoid is given by the formula $B = \mu_0 n i$, where $n$ is the number of turns per unit length $(n = m/\e

Vedclass · Accepted Answer

$500$

Vedclass · Answer

(A) The magnetic field $B$ inside a long solenoid is given by the formula $B = \mu_0 n i$, where $n$ is the number of turns per unit length $(n = m/\ell)$.Substituting the expression for $n$, we get $B = \mu_0 (m/\ell) i$.Rearranging the formula to solve for $m$: $m = (B 	imes \ell) / (\mu_0 	imes i)$.Given values: $B = 6.28 	imes 10^{-3} \,T$, $\ell = 0.5 \,m$, $i = 5 \,A$, and $\mu_0 = 4\pi 	imes 10^{-7} \approx 12.56 	imes 10^{-7} \,T \cdot m/A$.Substituting these values: $m = (6.28 	imes 10^{-3} 	imes 0.5) / (12.56 	imes 10^{-7} 	imes 5)$.$m = (3.14 	imes 10^{-3}) / (62.8 	imes 10^{-7}) = (3.14 	imes 10^{-3}) / (6.28 	imes 10^{-6}) = 0.5 	imes 10^3 = 500$.Therefore, the value of $m$ is $500$.

$A$ solenoid of length $0.5 \,m$ has a radius of $1 \,cm$ and is made up of $m$ number of turns. It carries a current of $5 \,A$. If the magnitude of the magnetic field inside the solenoid is $6.28 \times 10^{-3} \,T$, then the value of $m$ is:

Similar Questions

$A$ current of $1/4\pi \ A$ is flowing through a toroid. It has $1000$ turns per meter. The value of the magnetic field (in $Wb/m^2$) along its axis is:

$A$ long solenoid is formed by winding $70$ turns $cm^{-1}$. If $2.0\,A$ current flows,then the magnetic field produced inside the solenoid is $.......\times 10^{-4}\,T$ $\left(\mu_0 = 4\pi \times 10^{-7}\,TmA^{-1}\right)$

Two toroids $1$ and $2$ have total number of turns $200$ and $100$ respectively with average radii $40 \; cm$ and $20 \; cm$ respectively. If they carry the same current $i$,the ratio of the magnetic fields along the two loops is

The magnetic energy stored in a long solenoid of area of cross-section $A$ in a small region of length $L$ is

The magnetic field inside a $200$ turns solenoid of radius $10 \ cm$ is $2.9 \times 10^{-4} \ T$. If the solenoid carries a current of $0.29 \ A$,then the length of the solenoid is . . . . . . $\pi \ cm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module