$A$ solid piece of iron of dimensions $49 \times 33 \times 24 \text{ cm}$ is moulded into a sphere. The radius of the sphere is......$\text{cm}$.

The sum of the radius of the base and the height of a solid cylinder is $37 \, m$. If the total surface area of the cylinder is $1628 \, m^2$,find the volume (in $m^3$).

The base of a right pyramid is a square,and the length of the diagonal of the base is $24 \sqrt{2} \text{ m}$. If the volume of the pyramid is $1728 \text{ m}^3$,its height is ......... $\text{m}$.

$A$ solid sphere and a solid hemisphere have the same total surface area. The ratio of their volumes is

$A$ rectangular piece of paper is $22 \text{ cm}$ long and $10 \text{ cm}$ wide. $A$ cylinder is formed by rolling the paper along its length. The volume of the cylinder is

$A$ sphere is melted to form a cylinder whose height is $4 \frac{1}{2}$ times its radius. What is the ratio of the radius of the sphere to the radius of the cylinder?