$A$ solid sphere of mass $M$,radius $R$ and having moment of inertia about an axis passing through the centre of mass as $I$,is recast into a disc of thickness $t$,whose moment of inertia about an axis passing through its edge and perpendicular to its plane remains $I$. Then,the radius of the disc will be

  • A
    $\frac{2R}{\sqrt{15}}$
  • B
    $R\sqrt{\frac{2}{15}}$
  • C
    $\frac{4R}{\sqrt{15}}$
  • D
    $\frac{R}{4}$

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