A spring-mass system performs S.H.M. If the m | vedclass

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(C) The total energy $(E)$ of a spring-mass system performing $S.H.M.$ is given by the formula $E = \frac{1}{2} k A^{2}$,where $k$ is the spring const

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(C) The total energy $(E)$ of a spring-mass system performing $S.H.M.$ is given by the formula $E = \frac{1}{2} k A^{2}$,where $k$ is the spring constant and $A$ is the amplitude of oscillation.In this expression,the total energy depends only on the spring constant $(k)$ and the amplitude $(A)$.It is independent of the mass $(m)$ of the object attached to the spring.Since the amplitude $(A)$ is kept constant and the spring constant $(k)$ remains the same,the total energy of the $S.H.M.$ will remain unchanged even if the mass is doubled.

$A$ spring-mass system performs $S.H.M.$ If the mass is doubled keeping the amplitude same,then the total energy of $S.H.M.$ will become:

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