A steel rod of length 1,m and area of cross-s | vedclass

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(B) The change in temperature is $\Delta t = 200\,^{\circ}C - 0\,^{\circ}C = 200\,^{\circ}C$.The area of cross-section is $A = 1\,cm^2 = 10^{-4}\,m^2$

Vedclass · Accepted Answer

$4 	imes 10^4 \,N$

Vedclass · Answer

(B) The change in temperature is $\Delta t = 200\,^{\circ}C - 0\,^{\circ}C = 200\,^{\circ}C$.The area of cross-section is $A = 1\,cm^2 = 10^{-4}\,m^2$.When a rod is prevented from expanding,the thermal stress produced is given by $\sigma = Y \alpha \Delta t$.The tension force $F$ is given by $F = \sigma A = Y A \alpha \Delta t$.Substituting the given values:$F = (2.0 	imes 10^{11}) 	imes (10^{-4}) 	imes (10^{-5}) 	imes (200)$.$F = 2 	imes 10^{11} 	imes 10^{-9} 	imes 200$.$F = 2 	imes 10^2 	imes 200 = 400 	imes 100 = 4 	imes 10^4 \,N$.

$A$ steel rod of length $1\,m$ and area of cross-section $1\,cm^2$ is heated from $0\,^{\circ}C$ to $200\,^{\circ}C$ without being allowed to extend or bend. Find the tension produced in the rod $(Y = 2.0 \times 10^{11}\,N/m^2, \alpha = 10^{-5} \,^{\circ}C^{-1})$.

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