A stick of 1 , m is moving with a velocity of | vedclass

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(C) According to the theory of special relativity,the length of an object moving at relativistic speeds undergoes length contraction in the direction

Vedclass · Accepted Answer

$0.44$

Vedclass · Answer

(C) According to the theory of special relativity,the length of an object moving at relativistic speeds undergoes length contraction in the direction of motion.The formula for length contraction is $l = l_0 \sqrt{1 - \frac{v^2}{c^2}}$,where $l_0$ is the proper length,$v$ is the velocity of the object,and $c$ is the speed of light.Given: $l_0 = 1 \, m$,$v = 2.7 	imes 10^8 \, m/s$,and $c = 3 	imes 10^8 \, m/s$.Substituting the values into the formula:$l = 1 	imes \sqrt{1 - \left( \frac{2.7 	imes 10^8}{3 	imes 10^8} ight)^2}$$l = \sqrt{1 - (0.9)^2}$$l = \sqrt{1 - 0.81}$$l = \sqrt{0.19}$$l \approx 0.4358 \, m \approx 0.44 \, m$.Thus,the apparent length of the stick is $0.44 \, m$.

$A$ stick of $1 \, m$ is moving with a velocity of $2.7 \times 10^8 \, m/s$. What is the apparent length of the stick in meters? (Given: $c = 3 \times 10^8 \, m/s$)

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