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(A) The equation of motion is given by $s(t) = 490t - 4.9t^2$.To find the maximum height,we find the velocity $v(t)$ by differentiating $s(t)$ with re

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$12250$

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(A) The equation of motion is given by $s(t) = 490t - 4.9t^2$.To find the maximum height,we find the velocity $v(t)$ by differentiating $s(t)$ with respect to $t$:$v(t) = \frac{ds}{dt} = 490 - 9.8t$.At maximum height,the velocity $v(t) = 0$:$490 - 9.8t = 0 \implies 9.8t = 490 \implies t = \frac{490}{9.8} = 50 	ext{ seconds}$.Now,substitute $t = 50$ into the equation for $s$:$s(50) = 490(50) - 4.9(50)^2$$s(50) = 24500 - 4.9(2500)$$s(50) = 24500 - 12250 = 12250$.Thus,the maximum height reached by the stone is $12250$ units.

$A$ stone moving vertically upwards has its equation of motion $s = 490t - 4.9t^2$. The maximum height reached by the stone is

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