$A$ stone thrown upward with a speed $u$ from the top of a tower reaches the ground with a velocity $4 u$. The height of the tower is .........
- A$\frac{15 u^2}{2 g}$
- B$\frac{7 u^2}{2 g}$
- C$\frac{16 u^2}{g}$
- DZero
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Similar Questions
$A$ balloon rises up with a constant net acceleration of $10\,m/s^2$. After $2\,s$,a particle drops from the balloon. After a further $2\,s$,match the following columns. (Take $g=10\,m/s^2$)
Column $I$ Column $II$ $(A)$ Height of particle from ground $(p)$ $0$ $(B)$ Speed of particle $(q)$ $10$ $SI$ unit $(C)$ Displacement of particle $(r)$ $40$ $SI$ unit $(D)$ Acceleration of particle $(s)$ $20$ $SI$ unit
| Column $I$ | Column $II$ |
|---|---|
| $(A)$ Height of particle from ground | $(p)$ $0$ |
| $(B)$ Speed of particle | $(q)$ $10$ $SI$ unit |
| $(C)$ Displacement of particle | $(r)$ $40$ $SI$ unit |
| $(D)$ Acceleration of particle | $(s)$ $20$ $SI$ unit |
Difficult
View Solution$A$ ball is dropped downwards. After $1$ second,another ball is dropped downwards from the same point. What is the distance between them after $3$ seconds?
Medium
View Solution$A$ stone dropped from the top of the tower touches the ground in $4 \, s$. The height of the tower is about..........$m$.
Easy
View SolutionWhat is the ratio of the distances covered by a freely falling body in the $1^{st}$,$2^{nd}$,and $3^{rd}$ seconds of its motion?
Medium
View SolutionIf the distance travelled by a freely falling body in the last but one second of its motion is $5 \ m$,then the total time of motion is (Acceleration due to gravity $g = 10 \ m \ s^{-2}$) (in $s$)
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