A storage tank is in the form of a cube. When | vedclass

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(C) The volume of the cubic tank is $V_{total} = 15.625 \, m^3$. Since the tank is a cube, the side length $s$ is given by $s = \sqrt[3]{15.625} = 2.5

Vedclass · Accepted Answer

$7.5$

Vedclass · Answer

(C) The volume of the cubic tank is $V_{total} = 15.625 \, m^3$. Since the tank is a cube, the side length $s$ is given by $s = \sqrt[3]{15.625} = 2.5 \, m$. The current depth of water is $h = 1.3 \, m$. The volume of water currently in the tank is $V_{current} = 	ext{side} 	imes 	ext{side} 	imes 	ext{depth} = 2.5 	imes 2.5 	imes 1.3 = 6.25 	imes 1.3 = 8.125 \, m^3$. The volume of water already used is $V_{used} = V_{total} - V_{current} = 15.625 - 8.125 = 7.5 \, m^3$.

$A$ storage tank is in the form of a cube. When it is full of water, the volume of water is $15.625 \, m^3$. If the present depth of water is $1.3 \, m$, find the volume of water already used from the tank (in $m^3$).

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