$A$ stream of water flowing horizontally with a speed of $15\; m s^{-1}$ gushes out of a tube of cross-sectional area $10^{-2}\; m^2$,and hits a vertical wall nearby. What is the force in $N$ exerted on the wall by the impact of water,assuming it does not rebound?

Water flowing through a pipe of area of cross-section $2 \times 10^{-3} \,m^2$ hits a vertical wall horizontally with a velocity of $12 \,m \,s^{-1}$. If the water does not rebound after hitting the wall, then the force acting on the wall due to water is (in $\,N$)

$A$ fire hydrant delivers water of density $\rho$ at a volume rate $L$. The water travels vertically upward through the hydrant and then makes a $90^{\circ}$ turn to emerge horizontally at speed $V$. The pipe and nozzle have a uniform cross-section throughout. The force exerted by the water on the corner of the hydrant is

$A$ jet of liquid of cross-sectional area $a$ strikes a wall making an angle $\theta$ with the wall. The liquid strikes the wall with velocity $v$ and rebounds elastically. If the density of the liquid is $\rho$,the normal force on the wall is:

$A$ uniformly tapering vessel is filled with a liquid of density $900 \, kg/m^3$. The force that acts on the base of the vessel due to the liquid is ......... $N$. $(g = 10 \, m/s^2)$

An object is fitted in a hole at the base of a container as shown in the figure. The force due to the liquid on the object is (Assume no leakage of water,the volume of the object inside the container is $V$,and the density of the liquid is $\rho$):