A stretched string is vibrating in its 5^{th} | vedclass

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(C) In a stationary wave,all particles located between two consecutive nodes vibrate in the same phase.Particle $1$ is in the first loop (between the

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$5, 7, 8$

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(C) In a stationary wave,all particles located between two consecutive nodes vibrate in the same phase.Particle $1$ is in the first loop (between the first node and the first antinode).Particles in the same loop as particle $1$ will be in the same phase.Looking at the diagram,particles $2, 4, 6, 8$ are nodes,and particles $1, 3, 5, 7$ are in different loops.However,particles in alternate loops are in the same phase (phase difference of $2\pi$ or $0$).Particles in adjacent loops are in opposite phases (phase difference of $\pi$).Particle $1$ is in the first loop. The third loop contains particle $5$,and the fifth loop contains particle $7$.Thus,particles $1, 5,$ and $7$ are in the same phase.Therefore,the correct set is $5, 7, 8$ is incorrect based on the diagram labels,let's re-evaluate: The particles $1, 5, 7$ are in the same phase. Looking at the options,$5, 7$ are present in option $C$.

$A$ stretched string is vibrating in its $5^{th}$ harmonic as shown. Consider a particle $1$ (figure). At an instant,this particle is at its mean position and is moving towards its negative extreme. Which of the following sets of particles are in the same phase as particle $1$?

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