A suitable unit for gravitational constant is | vedclass

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(C) According to Newton's law of universal gravitation,the force $F$ between two masses $m_1$ and $m_2$ separated by a distance $d$ is given by:$F = \

Vedclass · Accepted Answer

$N \cdot m^2 \cdot kg^{-2}$

Vedclass · Answer

(C) According to Newton's law of universal gravitation,the force $F$ between two masses $m_1$ and $m_2$ separated by a distance $d$ is given by:$F = \frac{G m_1 m_2}{d^2}$Rearranging the formula to solve for the gravitational constant $G$:$G = \frac{F d^2}{m_1 m_2}$The $SI$ unit of force $F$ is Newton $(N)$,distance $d$ is meter $(m)$,and mass $m$ is kilogram $(kg)$.Substituting these units into the formula:$G = \frac{N \cdot m^2}{kg^2} = N \cdot m^2 \cdot kg^{-2}$Therefore,the correct unit is $N \cdot m^2 \cdot kg^{-2}$.

$A$ suitable unit for gravitational constant is

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