(C) Given that,Height $(h)$ of the cylindrical part $= 2.1 \, m$Diameter of the cylindrical part $= 4 \, m$Radius $(r)$ of the cylindrical part $= 2 \

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(C) Given that,Height $(h)$ of the cylindrical part $= 2.1 \, m$Diameter of the cylindrical part $= 4 \, m$Radius $(r)$ of the cylindrical part $= 2 \, m$Slant height $(l)$ of the conical part $= 2.8 \, m$Area of canvas used = $CSA$ of conical part + $CSA$ of cylindrical part$= \pi rl + 2\pi rh$$= \pi r(l + 2h)$$= \frac{22}{7} \times 2 \times (2.8 + 2 \times 2.1)$$= \frac{44}{7} \times (2.8 + 4.2)$$= \frac{44}{7} \times 7 = 44 \, m^2$Cost of $1 \, m^2$ canvas $= Rs. \, 500$Cost of $44 \, m^2$ canvas $= 44 \times 500 = Rs. \, 22000$Therefore,the cost of the canvas for making the tent is $Rs. \, 22000$.

Class 10 Mathematics Surface Areas and Volumes Textbook - Surface Areas and Volumes

Medium

$A$ tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are $2.1 \, m$ and $4 \, m$ respectively,and the slant height of the top is $2.8 \, m$,find the area of the canvas used for making the tent. Also,find the cost of the canvas of the tent at the rate of $Rs. \, 500$ per $m^2$. (in $Rs.$) [Use $\pi = \frac{22}{7}$] (Note that the base of the tent will not be covered with canvas.)

A
$22500$
B
$23000$
C
$22000$
D
$21000$

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Surface Areas and Volumes

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Textbook - Surface Areas and Volumes

$A$ copper wire,$3 \,mm$ in diameter,is wound about a cylinder whose length is $12 \,cm$ and diameter $10 \,cm$,so as to cover the curved surface of the cylinder. Find the mass of the wire,assuming the density of copper to be $8.88 \,g/cm^3$. (in $g$)

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$A$ container,opened from the top and made up of a metal sheet,is in the form of a frustum of a cone of height $16 \, cm$ with radii of its lower and upper ends as $8 \, cm$ and $20 \, cm$,respectively. Find the cost of the milk which can completely fill the container,at the rate of $Rs. \, 20$ per litre. Also,find the cost of the metal sheet used to make the container,if it costs $Rs. \, 8$ per $100 \, cm^2$. (Take $\pi = 3.14$)

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From a solid cylinder whose height is $2.4 \, cm$ and diameter is $1.4 \, cm$,a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest $cm^2$. [Take $\pi = \frac{22}{7}$]

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An oil funnel made of a tin sheet consists of a $10 \, cm$ long cylindrical portion attached to a frustum of a cone. If the total height is $22 \, cm$,the diameter of the cylindrical portion is $8 \, cm$,and the diameter of the top of the funnel is $18 \, cm$,find the area of the tin sheet required to make the funnel.

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$A$ farmer connects a pipe of internal diameter $20 \,cm$ from a canal into a cylindrical tank in her field,which is $10 \,m$ in diameter and $2 \,m$ deep. If water flows through the pipe at the rate of $3 \,km/h$,in how much time will the tank be filled? (in $minutes$) [Take $\pi = \frac{22}{7}$]

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$A$ copper wire,$3 \,mm$ in diameter,is wound about a cylinder whose length is $12 \,cm$ and diameter $10 \,cm$,so as to cover the curved surface of the cylinder. Find the mass of the wire,assuming the density of copper to be $8.88 \,g/cm^3$. (in $g$)

From a solid cylinder whose height is $2.4 \, cm$ and diameter is $1.4 \, cm$,a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest $cm^2$. [Take $\pi = \frac{22}{7}$]

$A$ farmer connects a pipe of internal diameter $20 \,cm$ from a canal into a cylindrical tank in her field,which is $10 \,m$ in diameter and $2 \,m$ deep. If water flows through the pipe at the rate of $3 \,km/h$,in how much time will the tank be filled? (in $minutes$) [Take $\pi = \frac{22}{7}$]

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